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Calculate the instantaneous speed and distance fallen for an object that falls freely from rest for 8 seconds.

Calculate the instantaneous speed and distance fallen for an object that falls freely from rest for 8 seconds. Explanation would be nice, and I should get rid of that part saying how I wanted the answer 71 mths ago

Best Answer

you just need to know that acceleration due to gravity is approx. 9.81 meters per second squared. The distance can be calculated with the formula s = u*t +1/2 a* t^2 s=distance, u=initial speed, t=time and a=acceleration since u=0 in this case we simply have s= 1/2 a* t^2..... here is my answer. s=1/2 *9.81*(6^2) = 176.58m final speed is given by v=a*t = 9.81*6 = 58.86 meters per second average speed is given by av=distance/time = 176.58/6 = 29.43 meters per second

Source: calculated

71 mths ago

Answers -

Holy smoke!!! The bright folks will have to answer this one. I won't even get out of the starting gate.

71 mths ago

1. What is its instantaneous speed? vo = 0 m/s, a = 10 m/s2, t = 8 s, v = ? v = at = (10 m/s2)(8 s) = 80 m/s 2. How far has it fallen? * a = 10 m/s2, t = 8 s, d = ? distance equation = 0.5(10 m/s2)(8 s)2 = 320 m * Or, d = vy/2 = 0.5(80 m/s)(8 s) = 320 m

71 mths ago

The previous method is correct, but the version of the question I see sets t = 8, not 6... so u = 0, t = 8, a = g = 9.81m/s^2, v = a*t = 78.48m/s and s = u*t + 0.5*a*t^2 = 313.92m

71 mths ago

No thank you! My head will hurt! :)

71 mths ago

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